(9y^2-5y+4)-(8y^2-5y+5)=

Solution for (9y^2-5y+4)-(8y^2-5y+5)= equation:

Simplifying
(9y2 + -5y + 4) + -1(8y2 + -5y + 5) = 0

Reorder the terms:
(4 + -5y + 9y2) + -1(8y2 + -5y + 5) = 0

Remove parenthesis around (4 + -5y + 9y2)
4 + -5y + 9y2 + -1(8y2 + -5y + 5) = 0

Reorder the terms:
4 + -5y + 9y2 + -1(5 + -5y + 8y2) = 0
4 + -5y + 9y2 + (5 * -1 + -5y * -1 + 8y2 * -1) = 0
4 + -5y + 9y2 + (-5 + 5y + -8y2) = 0

Reorder the terms:
4 + -5 + -5y + 5y + 9y2 + -8y2 = 0

Combine like terms: 4 + -5 = -1
-1 + -5y + 5y + 9y2 + -8y2 = 0

Combine like terms: -5y + 5y = 0
-1 + 0 + 9y2 + -8y2 = 0
-1 + 9y2 + -8y2 = 0

Combine like terms: 9y2 + -8y2 = 1y2
-1 + 1y2 = 0

Solving
-1 + 1y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 1y2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 1y2 = 0 + 1
1y2 = 0 + 1

Combine like terms: 0 + 1 = 1
1y2 = 1

Divide each side by '1'.
y2 = 1

Simplifying
y2 = 1

Take the square root of each side:
y = {-1, 1}